Solving Linear Equations - MR. CADMAN'S Site

Solving Linear Equations Recall: Order of Operations (BEDMAS) 1. 2. 3. 4. Evaluate expressions within brackets. Evaluate all exponents. Multiply and divide from left to right. Add and subtract from left to right. Try to Solve: (2+3) x 5 2 x (3 + 10 2) =9 = 12 What was my starting number?

x ? Add 2 +2 x+2 Multiply by 5 x5 5 x 2 Subtract 4 -4 5 x 2 4 Divide by 8 8

5 x 2 4 8 18 -2 5 +4 x8 20 100 96 12 Using Algebra to Solve Equations Find the solution to the equation: Need to isolate the variable tem

Subtract 15 to each side -15 5b 5b + 15 = -5 = -15 = -20 Divide each side by 5 5 5 b =-4 Verify the solution: 5b + 15 = -5 5(-4) +15 = -5

-20 +15 = -5 -5 = -5 Solution is correct. Using Algebra to Solve Equations Find the solution to the equation: Add 69 to each side +69 16t 16t - 69 = -13 = +69 = 56 Divide each side by 16

16 16 t= Because 56 16 is not a whole number you have two options: As a fraction divide by the common factor of 8 8 = As a decimal, simply divide = 3.5 Equation: 13 2x =5 -13 = -13 -2x= -8

-2 = -2 1x = Isolate the Variable Term 1) Subtract 13 for each side 2) Divide each side by -2 x =, now you need verify you solution. Substitute into equation and check if equation is valid 13 - 2 (4) = 5 13 - 8 =5 5 =5 Solution is correct Equation: 3 + 2t -3 Isolate the Variable Term 1) Subtract 3 for each side 2) Divide each side by 2 =4

= -3 2x = 1 2 =2 1x = x is equal to , now you need to verify you solution. Substitute into equation and check if equation is valid 3 + 2 () =4 3+1 =4 4 =4 Solution is correct Combine Like terms Equation: 1 + 2x + 3 =8 1+3 + 2x =8 4 + 2x = 8 -4

= -4 2x = 4 2 =2 1x = 2 Isolate the Variable Term 1) Subtract 4 for each side 2) Divide each side by 2 x is equal to 2, now you need to verify your solution. Substitute 2 into equation and check if equation is valid 1 + 2(2) + 3 =8 1+4+3 =8 8 =8 Solution is correct Classwork page 331 #6, 8, 9, 11

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